能量动法 MAB(x)=Px moaB(x)=x Mnc(xi)=0.3P MnocA(x)=0.3 ③变形 r M,(XM,o(x M(x)M(r) B 1dx,+ d L G 丿L P El 0.5 0.3P×0.3 0.3 Px dx,+ PL ax= AB +I PL ABAC 0 GIp 1 El BEI AB GIP 60×0.3×12 3×210×5X103×103+0.3×003×0.5×312103 × 0.4×210×204x =8.22mM x Px AB( ) = M x x 0AB( ) = MnCA(x1 ) = 0.3P Mn0CA(x1 ) = 0.3   = + L L P n n B x EI M x M x x G I M x M x d ( ) ( ) d ( ) ( ) 0 1 1 0 1    +  = 0.3 0 0.5 2 0 d 1 d 0.3 0.3 x EI Px x GI P P P AB AC AB AB GI PL L L EI PL = + 3 3  +      = 3 3 3 10 3 210 5 10 60 0.3 12 3 4 10 0.4 210 20 60 0.3 0.5 32 0.3         = 8.22mm ③变形