解 IN 00 00000 000 112233-44 00a1 23 (-1) ((432l) 0 0 000 1423u3341 1423u3341 32 41 其中t(4321)=0+1+2+33解： 11 22 1 33 44 0 0 0 0 0 0 0 0 0 0 0 0 a a D a a = 14 23 2 32 41 0 0 0 0 0 0 0 0 0 0 0 0a a D a a = 11 22 33 44 = a a a a (4321) 14 23 33 41 ( 1)t = − a a a a 14 23 33 41 = a a a a t(4321) 0 1 2 3 = + + + 3 4 6. 2 其中 = =