3-h()=1T-τ e 3-2(1)k(t)=10h(t)=10t 25 32(2)k(t)=esin4th(t)=1-esin(4t+53.13) 0.0125 3-3(1)@(s)= (2)Φ(s)=+ 5√50(s+4 s+l.25 (3)m=、0,1 s2+16 s(3s+1) 3-42=06 0%=948%tn=196t,=297s 35r=1.00660n.=15=0.5x=2.5B= l.686 t=145tn=3.156t,=601330%=199% 3-65=143an=2453-7k1=144k2=0.31 3-8(a)=0an=1系统临界稳定 s+l s+界+!5=0.5m,=1σ%=29.8%t=7.5ls (c)(s)= s4+s+1 5=0.5an=1σ‰=163%t,=8.08 3-9(1 (b)比(c)多一个零点附加零点有削弱阻尼的作用。 G(s)= k=55 =√10a%=3509%t=3.5s 0.2 S(0.5s+1 (2)G(s)= 10(0.Is+1 k=105 10z=10 B4=.249 S(S+1) 10 y %=37.06%t,=3 0.1（3-1题~3-9题） 3-1 T t h(t) 1 e T T −  − = − 3-2 (1) k(t ) = 10 h(t ) = 10t 3-2 (2) e sin4t 4 25 k(t ) −3t = e sin( 4t 53.13 ) 4 5 h(t ) 1 3t o = − + − 3-3 (1) s 1.25 0.0125 ( s ) +  = (2) s 16 50(s 4 ) s 5 (s) 2 2 + +  = + (3) s( 3s 1 ) 0.1 ( s ) +  = 3-4 0.6 2 % 9.478% t 1.96s t 2.917 s  = n =  = p = s = 3-5 r 1.0066 1 0.5 z 2.5 1.686 = n =  d = =  = 2  = −  t r = 1.45s t p = 3.156s t s = 6.0133s %= 17.99% 3-6  = 1.43 n = 24.5 3-7 k1 = 1.44 k2 = 0.311 3-8 (a)  = 0 n = 1 系统临界稳定 (b) 0.5 1 % 29.8% t 7.51s s s 1 s 1 (s ) 2 = n = = s = + + +  =    (c) 0.5 1 % 16.3% t 8.08s s s 1 1 (s ) 2 = n = = s = + +  =    (b)比(c)多一个零点,附加零点有削弱阻尼的作用。 3-9 (1) 10 % 35.09% t 3.5s e 0.2 10 1 k 5 s( 0.5s 1 ) 5 G(s ) = = n = = s = ss = + =    (2) 10 z 10 r 1 1.249 10 1 k 10 s(s 1 ) 10( 0.1s 1 ) G(s ) = = n = = = d = + + =    % 37.06% t 3s e 0.1 2 = −  = s = ss =  