ORGANIC CHEMISTRY Chapter 14 △H°(kJ/mo1) Pt 120 +2H2 32 +3H 208 120×3=360(kJ/mo) 360-208=152 (kJ/mol)-Resonance energy Department of Chemistry, Xiamen UniversityORGANIC CHEMISTRY Department of Chemistry, Xiamen University Chapter 14 ∆H°( kJ/mol) + H2 Pt + 2H2 Pt + 3H2 Pt 120 232 208 120 3 = 360 (kJ/mol) 360 208 = 152 (kJ/mol) —— Resonance energy