思考题解答 s={2m,n,6+p},且有≠0. s·k=0,s·i=0 「6+p=0 → P=-6,m=0 2m=0 s≠0,∴n≠0 故当m=0,n≠0,P=-6时结论成立 上页思考题解答 s = {2m, n, 6 + p},  且有 0.   s  s  k = 0,    s  i = 0,      = + =  2 0 6 0 m p  p = −6, m = 0, 0,    s   n  0, 故当 m = 0, n  0, p = −6 时结论成立．