1)先消元电流l GU21-G2U31+G5U/14=G1US1 GU21-G3U32+G4U24=-1U1+ls3+G4Cs4 GU3+GU32-G43=-k3 U21+U14-U24=0 3l-043 Un4=0 14 24 43 +∪3• 1）先消元电流 Ii。 −G1U21−G2U31+G5U14 =G1US1 G1U21−G3U32+G4U24 = −G1US1+ IS3+G4US4 G2U31+G3U32−G6U43 = −IS3 U21 + U14 – U24 = 0 -U31 – U43 – U14 = 0 U24 + U43 + U32 = 0