A B p.S A P4=Y·△H+PB =(133.32×300)Pa+355600Pa =0.3956Pa Pa=Po+Pea pe4=p4-p,=0.3956MPa-0.101325MPa=0.2943MPa 上游气通大粤 February 28,2019 22 SHANGHAI JLAO TONG UNIVERSITYFebruary 28, 2019 22 (133.32 300) Pa 355 600 Pa 0.395 6 MPa p H p A B         b e e b 0.395 6 MPa 0.101 325 MPa 0.294 3 MPa A A A A p p p p p p       