(2)由换路定则,u(0+)=(0)=10V i(0)=i1(0)=5A,作t=0+等效图 i(0+) t=0图 +a1(0)-a(0-)a(0)=10-(0)=0 22i4()i(0) i(0+)=uC(0)/4=25A 10V4g (0+)13 (2)由换路定则， ,作t =0 i L (0 + ) = i L (0 − ) = 5 A +等效图 C (0 ) = (0 ) =10 V + − u uC (0 ) 10 (0 ) 0 L = − = + + u uC 1 (0 ) = (0 )/ 4 = 2.5A + + uC i + uC (0+ ) - t=0+图 + 10V - + uL (0+ ) - iC (0+ ) iL (0+ ) 2 4 i1 (0+ ) i2 (0+ )