178 9 Effective Elastic Constants of a Laminate EDU>>Qbar6 Qbar(Q,30) Qbar6 91.1488 31.7170 95.3179 31.7170 19.3541 29.0342 47.6589 14.5171 61.8034 Next,the distances zk(k =1,2,3,4,5,6,7)are calculated as follows: EDU>>z1=-0.450 z1= -0.4500 EDU>>z2=-0.300 z2= -0.3000 EDU>>z3=-0.150 z3= -0.1500 EDU>>z4 =0 z4= 0 EDU>>z5=0.150 z5= 0.1500 EDU>>z6=0.300 z6= 0.3000 EDU>>z7=0.450 z7= 0.4500178 9 Effective Elastic Constants of a Laminate EDU>> Qbar6 = Qbar(Q, 30) Qbar6 = 91.1488 31.7170 95.3179 31.7170 19.3541 29.0342 47.6589 14.5171 61.8034 Next, the distances zk (k = 1, 2, 3, 4, 5, 6, 7) are calculated as follows: EDU>> z1 = -0.450 z1 = -0.4500 EDU>> z2 = -0.300 z2 = -0.3000 EDU>> z3 = -0.150 z3 = -0.1500 EDU>> z4 = 0 z4 = 0 EDU>> z5 = 0.150 z5 = 0.1500 EDU>> z6 = 0.300 z6 = 0.3000 EDU>> z7 = 0.450 z7 = 0.4500