点击下载:清华大学:《编译原理》课程教学资源_(英文译文)Chapter 8 Code Generation
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2*a+(b-3 )with syntax tree a The corresponding three-address code is T1=2*a T2=b-3 T3=t1+t22*a+(b-3) with syntax tree + * - 2 a b 3 The corresponding three-address code is T1 = 2 * a T2 = b – 3 T3 = t1 + t2
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点击下载:清华大学:《编译原理》课程教学资源_(英文译文)Chapter 8 Code Generation
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