掘转( Torsion M B 解:计算外力偶矩 M}=9549 kw n r/min Mn1=15915N·m 2 M2=4774.5N e4=6366Nm(Torsion) 解: 计算外力偶矩       / = kw e r min 9 549 p M n 6366 N m 4774.5 N m 15915 N m e4 e2 e3 e1 =  = =  =  M M M M Me4 A B C D Me1 Me2 Me3 n