SEPARATION FACTOR INTERPRETATION By the guideline for choosing the key components j and k Sr: >1 and SR <I Therefore SFik>I o IsIk =1, there is no separation. Numerical examples for separation factors E FR=0.9 for j and O I for k Then SF=9x9=81 E FR=0.95 forj and 0.05 for k Then sF=19 x 19 =361 E FR=0.99 forj and 0.0l for k. Then sf=99x 99=9801 In industrial practice, separation factors of 10,000 or more are not uncommon 94/99 Separation Operations: Introduction9/4/99 Separation Operations: Introduction 13 SEPARATION FACTOR INTERPRETATION uBy the guideline for choosing the key components j and k SRj > 1. and SRk < 1. Therefore SFjk > 1. u If SFjk = 1., there is no separation. u Numerical examples for separation factors ð FR = 0.9 for j and 0.1 for k. Then SF = 9 x 9 = 81 ð FR = 0.95 for j and 0.05 for k. Then SF = 19 x 19 = 361 ð FR = 0.99 for j and 0.01 for k. Then SF = 99 x 99 = 9801 In industrial practice, separation factors of 10,000 or more are not uncommon