解法2：已知TP1的△G1,求TP2的△G2 298K,P=P*,△G1=0; P2=P,△G2? =Vn,1-Vm,g≈-Vm,g △G2△G1=△G2 ∫yadP=RTLn =-8585J/mo113 解法 2：已知 TP1 的ΔG1，求 TP2的ΔG2 298K，P1 =P*，ΔG1 =0； P2 =Pθ ,ΔG2 =？ T P G ( )   = T P G ( ) 2   - T P G ( ) 1   =Vm，l -Vm，g ≈-Vm，g ΔG2 -ΔG1 =ΔG2 = V dP P P  g *  =RTLn  P P * =-8585J/mol