(3)计算围护结构内部各层的温度和水蒸气分压力 6,=16- 0.115 0.619 ×(16+4)=12.3℃，pg=14292Pa p:=1090.3Pa 6,=16-0.115i8.025×(16+4)=11.5℃，pe=1355.9Pa 0.619 =1090.3-366留 2517.13 ×(1090.3-218.7)=1032.6Pa 0,=16-0.15+02+0.263×(16+4)=3℃，p8÷757.3Pa 0.619 p=1090.3-166.7吉251.51×(1090,3-218.7)=945.5Pa 2517.13 a.=16-0.15+0.025+0263+0.173×(16+4)=-2.61℃，p=492R 0.619 p。=218.7Pa