STRUCTURE AND PRE TION OF ALKENES: ELIMINATION REACTIONS 5.8 The most stable CH, alkene has a tetrasubstituted double bond CH CH 5.9 Apply the two general rules for alkene stability to rank these compounds. First, more highly substi tuted double bonds are more stable than less substituted ones second when two de bonds are imilarly constituted, the trans stereoisomer is more stable than the cis. The predicted order of de creasing stability is therefore: H CHCH CH,CH,CH CHCH 2-Methyl-2-butene (E)-2-Pentene (disubstituted most stable 5.10 Begin by writing the structural formula corresponding to the IUPAC name given in the problem. A bond-line depiction is useful here 3,4-Di-1ert-butyl-2, 2, 5. 5-tetramethyl-3-hexene The alkene is extremely crowded and destabilized by van der Waals strain Bulky tert-butyl groups are cis to one another on each side of the double bond. Highly strained compounds are often quite difficult to synthesize, and this alkene is a good 5.11 Use the zigzag arrangement of bonds in the parent skeleton figure to place E and Z bonds as appro- priate for each part of the problem. From the sample solution to parts(a)and(b), the ring carbons have the higher priorities. Thus, an E double bond will have ring carbons arranged and a Z double bond (Z)-3-Methylcyclodecene (Z)-5-Methylcyclodecene H H CH (E)-3-Methylcyclodecene E)-5-Methylcyclodecene 5.12 Write out the structure of the alcohol, recognizing that the alkene is formed by loss of a hydrogen nd a hydroxyl group from adjacent carbons Back Forward Main Menu TOC Study Guide Toc Student OLC MHHE Website5.8 The most stable C6H12 alkene has a tetrasubstituted double bond: 5.9 Apply the two general rules for alkene stability to rank these compounds. First, more highly substi￾tuted double bonds are more stable than less substituted ones. Second, when two double bonds are similarly constituted, the trans stereoisomer is more stable than the cis. The predicted order of de￾creasing stability is therefore: 5.10 Begin by writing the structural formula corresponding to the IUPAC name given in the problem. A bond-line depiction is useful here. The alkene is extremely crowded and destabilized by van der Waals strain. Bulky tert-butyl groups are cis to one another on each side of the double bond. Highly strained compounds are often quite difficult to synthesize, and this alkene is a good example. 5.11 Use the zigzag arrangement of bonds in the parent skeleton figure to place E and Z bonds as appro￾priate for each part of the problem. From the sample solution to parts (a) and (b), the ring carbons have the higher priorities. Thus, an E double bond will have ring carbons arranged and a Z double bond . 5.12 Write out the structure of the alcohol, recognizing that the alkene is formed by loss of a hydrogen and a hydroxyl group from adjacent carbons. H H CH3 CH3 1 2 H H 2 3 5 4 1 3 (Z)-3-Methylcyclodecene (E)-3-Methylcyclodecene (E)-5-Methylcyclodecene (Z)-5-Methylcyclodecene H 1 2 3 4 5 H CH3 H H CH3 2 3 1 (c) (d) (e) (f) 3,4-Di-tert-butyl-2,2,5,5-tetramethyl-3-hexene C C CH3 CH3 CH3 H 2-Methyl-2-butene (trisubstituted): most stable C C CH3 CH2CH3 H H (E)-2-Pentene (disubstituted) C C CH3 CH2CH3 H H (Z)-2-Pentene (disubstituted) C C CH2CH2CH3 H H H 1-Pentene (monosubstituted): least stable C C CH3 CH3 CH3 CH3 2,3-Dimethyl-2-butene STRUCTURE AND PREPARATION OF ALKENES: ELIMINATION REACTIONS 93 Back Forward Main Menu TOC Study Guide TOC Student OLC MHHE Website