Thus: x=l f:PC6=4.16*10J1m.K,k,≈k,=0.5W1mK =10r% then: 1。=11.6588*10(4,6) An index for blood-tissue heat transfere x =l bCb = 4.16*10 J / m ⋅K, k b ≈ k t = 0.5W / m⋅K 6 3 ρ t b r =10r Thus: If: 11.6588*10 ( ) 6 2 e b b then: l = u r An index for blood-tissue heat transfer An index for blood-tissue heat transfer An index for blood-tissue heat transfer An index for blood-tissue heat transfer