2 FALL 2017 where l>0.Then A=LL'gives the equations 12,=5 l2l=-1 41-3 l21L21+52=2 l121+l2l2=-2 lg11+l4232+保=3 So we solving out all the entries of L in the order.2 FALL 2017 where lii > 0. Then A = LL∗ gives the equations l 2 11 = 5 l21l11 = −1 l31l11 = 3 l21¯l21 + l 2 22 = 2 l31¯l21 + l32l22 = −2 l31¯l31 + l32¯l32 + l 2 33 = 3 So we solving out all the entries of L in the order l11, l21, l31, l22, l32, l32