例22:用图解法画出本题的执行过程 #include <iostream.h> void main( int temp valuel=10, value2=20 int*ptr ptr=&valuel temp ="ptr ptr= value2 value2 =temp cout<<value l<<endl cout<<value2<<endl例2-2： #include <iostream.h> void main() { int temp ,value1 = 10, value2 = 20; int *ptr ; temp = *ptr; *ptr = value2; value2 = temp ; } ptr = &value1 ; cout<<value1<<endl; cout<<value2<<endl; 用图解法画出本题的执行过程