ORGANIC CHEMISTRY Chapter 10 hy CH3CHCH2CH3+C235° ChaCH CHCHCI 28% CH3 CH2 CHCH3 72% C V(1°H):V(2°H)=28/6:72/4=1:4 hv CHr chcha t c 35 o(CH3)2 CHCh2Cl+(Ch3)3 CCI CH 63 37% V(1°H:V(3H)=63/9:37/1=1:53 V(1°H):V(2H):V(3°H)=1:4:53 Department of Chemistry, Xiamen UniversityORGANIC CHEMISTRY Department of Chemistry, Xiamen University Chapter 10 CH3CH2CH2CH3 + Cl2 hv 35 72% CH3CHCH3 + Cl2 (CH3)2CHCH2Cl + (CH3)3CCl hv 35 CH 63% 37% 3 V(1 H)：V(2 H) = 28 / 6 ：72 / 4 =1：4 V(1 H)：V(3 H) = 63 / 9 ：37 / 1 =1：5.3 V(1 H)：V(2 H) ： V(3 H) =1：4：5.3 CH3CH2CHCH3 Cl CH3CH2CH2CH2Cl + 28%