3/2 1/2 V1s=V1.0 C 0 4兀 l/2 2 2.0.0 e 2 4兀 3/2 1/2 3 2,1,0 cos e 2√6(a 4兀 0 3/2 2 V2p2=V2,1.1(-1) sin ecos 0 4兀 0 3/2 1/2 3 py 2,1,-1(1) 2√6 0 4兀 Q e-r/2do sin sin p 3/2 1/2 27-18+2 r/3a0 0081√3 4兀 00 / 3/ 2 1/ 2 0 1 1,0,0 4 1 1 2 r a s e a −               = =    2 0 / 0 3/ 2 1/ 2 0 2 2,0,0 2 4 1 1 2 2 1 r a s e a r a −          −              = =        cos 4 1 3 2 6 1 2 0 / 0 3/ 2 1/ 2 0 2 2,1,0 r a p e a r a z −                       = =      sin cos 4 1 3 2 6 1 2 0 / 0 3/ 2 1/ 2 0 2 2,1,1( 1) r a p e a r a x − −                       = =      sin sin 4 1 3 2 6 1 2 0 / 0 3/ 2 1/ 2 0 2 2,1, 1(1) r a p e a r a y − −                       = = 3 0 / 2 0 2 0 3/ 2 1/ 2 0 3 3,0,0 27 18 2 4 1 1 81 3 1 r a s e a r a r a −          − +              = =   