例10求lim( 解原式=lim(1+1)-= x→0 例11求im 3+x\2 x→>∞2+x 解原式=lim(1+ x+212 ×(1+) x→0 x+2 x+2 =e2×1=e2. Economic-mathematics 16-16 Wednesday, February 24, 2021Economic-mathematics 16 - 16 Wednesday, February 24, 2021 例10 ) . 1 lim(1 x x x − → 求 解 1 ) ] 1 lim[(1 − − → − = + x x x 原式 . −1 = e 例11 ) . 2 3 lim( 2 x x x x + + → 求 解 2 2 ) ] 2 1 lim[(1 + → + = + x x x 原式 1 . 2 2 = e  = e 4 ) 2 1 (1 − +  + x