Lemma(Sperner) LetF().Then n-k F列≥太+i列 (for k <n) n(for k △F1≥ double counting R={(S,T)S∈F,T∈VF,ScT} VS∈F, n-kT∈(r)have TS 1R=(n-k)儿F到 VTVF,T has ()+1 many k-subsets |R≤(k+1)川VFLet F [n] k ⇥ . Then |⇧F| ⇥ n k k + 1 |F| |F| ⇥ k n k + 1|F| (for k<n) (for k > 0) Let F [n] k ⇥ . Then |⇧F| ⇥ n k k + 1 |F| |F| ⇥ k n k + 1|F| (for k<n) (for k > 0) Lemma (Sperner) double counting ⇥S F, n k T ⇤ [n] k+1⇥ have T ⇥ S R = {(S, T) | S ⇥ F, T ⇥ F, S T} |R| = (n k)|F| ⇥T ⌅F, T has k+1 k ⇥ = k + 1 many k-subsets |R| (k + 1)|⇧F|