直流(静态)分析 (1)估算法求Q点 (5)VcE=4V→Rb1=? 射极偏置:WB1+=Rn=C、vnBB2,(c-VB) R B 20k b2 60k+20k 16-55 20x 38.2AQ Je KVL:Ic≈lg B BE 5.5 R 4-0.7 Vn≈lcke+BE 1.65mA =2.4×2+0.7=5.5 lc165 T放大:IB =27.54 B60 Jc KVL: VCE=VCC -Ic(R+Re) CC CE 16-4 =16-1.65×(2+3) CRtr 2+3s2.4m4V V k k k V R R R V CC b b b B 16 4 60 20 20 1 2 2  = + =  + = V VCE VCC I C Rc Re 16 1.65 (2 3) 7.75 ( ) = −  + = = − + 直流（静态）分析 mA R V V I I e B BE C E 1.65 2 4 0.7 = − = −  = A I I C B   27.5 60 1.65 = = = 射极偏置： Je KVL： T放大： Jc KVL： （1）估算法求Q点： （5）VCE = 4V →Rb1=? mA R R V V I c e CC CE C 2.4 2 3 16 4 = + − = + − = V VB I C Re VBE = 2.42 + 0.7 = 5.5  + =  − =  =  − − = k k V V V R R V V V R CC B B b b B CC B b 38.2 5.5 16 5.5 20 ( ) 2 2 1