Ballistic Pendulum Stage 1: Momentum is conserved m in x-direction: mv=(m+M)V m+M Stage 2: Energy is conserved (EI=EF) 2(m+M)V2=(m+M)gH ) V2=2gH Eliminating v gives m/V<9 Physics 121: Lecture 16, Pg 8Physics 121: Lecture 16, Pg 8 Ballistic Pendulum... Stage 1: Momentum is conserved in x-direction: mv = (m + M )V V m m M = v +       Stage 2: Energy is conserved (E E ) I = F 1 2 2 (m + M )V = (m + M )gH V gH 2 = 2 Eliminating V gives: 2gH m M v 1       = +