分别沿y=x与y=x3算出积分 1 (x+iy)d z 沿y=x x+jy=(1+i) d==(1+i)dx (x2+y)l=(x2+ix)(1+1)k 0 3 1+(2+12)b=(+(沿 y=x z x iy i x = + = + (1 ) , dz i dx = + (1 ) , 1 1 2 2 0 0 ( ) ( )(1 ) , i x iy dz x ix i dx + + = + +   3 2 1 0 1 1 (1 )( ) (1 )( ) 3 2 3 2 x x = + + = + + i i i i 1 5 6 6 = − + i z