使用示例 bitSet<int>s1,s2,s3,s4,s5;bool index,equal; for (int k=0;k<10;k++ /集合赋值 s1.addMember (k); s2.addMember(k+7); /s1:{0,1,2,,9}, s2:{7,8,9,,16} s3=S1+s2; 1/求s1与s2的并{0,1，，16} s4=S1*s2; 1/求s1与s2的交{7,8,9} s5=s1-s2; /求s1与s2的差{0,1，，6 10使用示例 bitSet<int> s1, s2, s3, s4, s5; bool index, equal; for (int k = 0; k < 10; k++) { //集合赋值 s1.addMember (k); s2.addMember(k+7); } //s1: {0, 1, 2, …, 9}, s2: {7, 8, 9, …, 16} s3 = s1+s2; //求s1与s2的并 {0, 1, …, 16} s4 = s1*s2; //求s1与s2的交 {7, 8, 9} s5 = s1-s2; //求s1与s2的差 {0, 1, …, 6} 10