7.11某沉淀物中含有3.9%NaC1,9.6%AgC1,现欲以1L氨水将该沉淀物300g溶解，问氨水 最低浓度应为多少？（生成AgNH)2) 答案： AgCl= Ag* Cl NH3/\CI 300×3.9%+300×9.66=0.40mol-L [Cr]=M(NaC)M(AgC)) [Ag]=300x969% 0.20molL M(AgCI) QAgC=1+[CI]B+.+[C]4B=1045 [Ag]= K(AgCD)K(AgCD)=020 [c-] [c] 0.20x0.40-10-) aAg=1095 @Ag(NH)=1+[H2B+[NH3P=10840 10840 [NH,1=102w=32mol-L c(NH3)=[NH ]+2[Ag ]3.6mol.L7.11 某沉淀物中含有 3.9%NaCl，9.6%AgCl，现欲以 1L 氨水将该沉淀物 300g 溶解，问氨水 最低浓度应为多少？（生成 Ag(NH3)2 +） 答案： AgCl= Ag+ + Cl- NH3 / \Cl- [Cl- ]= -1 0.40mol L (AgCl) 300 9.6% (NaCl) 300 3.9% =   +  M M -1 0.20mol L (AgCl) 300 9.6% [Ag'] =   = M Ag(Cl)=1+[Cl- ]1+…+[Cl- ] 44=104.5 0.20 [Cl ] (AgCl) [Cl ] (AgCl) [Ag'] sp Ag ' sp =  = = − − K K  Ag= Ag(NH ) Ag(Cl) Ag(NH ) 8.40 9.5 3 3 10 10 0.20 0.40 = =  +    − Ag(NH ) 3  =1+[NH3] 1+[NH3] 22=108.40 -1 3 3 1 7.40 8.40 3 (NH ) [NH ] 2[Ag'] 3.6mol L 3.2mol L 10 10 [NH ] = + =  = =  − c