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0.1 3=(1+k K 2)2=1.1133 K4=(+0.1K3)2=12351 0.1 y1=y+(K1+2K2+2K3+K4)=1.1111 其余结果如下 n Xn k1 k2 k3 k4 yn 1.00000.10001.00001.10251.1133123511.111 2.00000.20001.23461.37561.39211.56331.2500 3.00000.30001.56251.76391.79082.042314286 4.00000.40002.04082.34282.38922.78051.6667 5.00000.50002.7777326003.34764.00572.00002 3 0 2 ) 2 0.1 K = ( y + K = 1.1133 2 4 0 3 K = ( y + 0.1K ) = 1.2351 ( 2 2 ) 6 0.1 1 0 K1 K2 K3 K4 y = y + + + + = 1.1111 其余结果如下: n xn k1 k2 k3 k4 yn 1.0000 0.1000 1.0000 1.1025 1.1133 1.2351 1.1111 2.0000 0.2000 1.2346 1.3756 1.3921 1.5633 1.2500 3.0000 0.3000 1.5625 1.7639 1.7908 2.0423 1.4286 4.0000 0.4000 2.0408 2.3428 2.3892 2.7805 1.6667 5.0000 0.5000 2.7777 3.2600 3.3476 4.0057 2.0000
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