第6章第9节 例4P12067 1)分解因子 2)综合 maino main i int a, sum, i; fint k,i, a, sum; printf(“ input a data:“) for(k=1;k<=1000,k++) scanf“%d”,a); fa=k; sumI; printi(“% d its factors are:l”,a): printf("%d it's factors are: 1,k); sum=l r(i=2;i<=a;i++) for (i=2; i<=a; i++ Rif(a%1-=0) Rif(a%i==0 Rprint“%d”,j) printf(“%d”,i); sum=sum+ sum=sum+I a=a/ a-a /i: i=1;} t“n”) if(sum==k print“% d is one of the resulteln”,k); getchar(;第6章 第9节 例4 P120 6.7 1)分解因子 main() { int a, sum,i; printf(“input a data: “); scanf(“%d”,&a); printf(“%d its factors are : 1 ”, a); sum=1; for (i=2; i<=a;i++) {if(a%i= =0) {printf(“%d ”,i); sum=sum+i; a=a/i; i=1;} } } 2)综合： main( ) {int k,i,a,sum; for(k=1;k<=1000,k++) {a=k; sum=1; printf(“%d it’s factors are : 1 ”, k); for (i=2; i<=a;i++) {if(a%i==0) {printf(“ %d”,i); sum=sum+i; a=a/i; i=1;} } printf(“\n”); if (sum= =k) {printf(“%d is one of the resulte\n”, k); getchar(); } } }