Solution If the projectile had not exploded, the location of the projectile at t=1.42s should have been x=vot=(7.3m/s)×142s=10.4m g (10.0m/s)×(1.42.)-(9.80m/s2)×(142s) 4.3 It is the location of the cm 1x1+m2 1,y+mly m, +mSolution: If the projectile had not exploded, the location of the projectile at t=1.42s should have been It is the location of the CM. x = v0x t = (7.3m/s)1.42s =10.4m m m s s m s s y v t gt y 4.3 (9.80 / ) (1.42 ) 2 1 (10.0 / ) (1.42 ) 2 1 2 2 2 0 = =  −  = − 1 2 1 1 2 2 m m m x m x xcm + + = 1 2 1 1 2 2 m m m y m y ycm + + = ? ?