上游充通大粤 SHANGHAI JIAO TONG UNIVERSITY 9.1 Freezing point depression (5) L(Tn-T) RT Example: 1mol%of lead added to silver caused lowering of melting point of silver. Tm=1234K,L=11300J/mol T R(T)2xg 人S 8,314*12342*0.01=11.2K Liquid 47s L 11300 L+S Phase rule: AF=C-P+1=2-2+1=1 Therefore,once the temperature is specified,the composition is also fixed. XB1 X What about the quantifies of the phases?9.1 Freezing point depression (5) Tm T Liquid L+S T1 xB1 x Example: 1mol% of lead added to silver caused lowering of melting point of silver. Tm = 1234 K, L = 11300 J/mol K L R T x T B 11.2 11300 ( ) 8.314*1234 *0.01 2 2 m     Phase rule: F = C – P + 1 = 2 – 2 + 1 = 1 Therefore, once the temperature is specified, the composition is also fixed. What about the quantifies of the phases?