分析举例 T ~“令令 RLI β(R3∥R2) R2=R5∥[2+(1+B2)(R6∥R1 2=(+B1)(R∥R)R=R∥R,∥rs ea+(1+B2)(R∥R) R R5+ 1+B[ (1 )( )] i 2 5 be2 2 R6 RL R = R ∥ r + +  ∥ 1 2 be2 2 6 L 2 6 L 2 b e1 3 i 2 1 (1 ) ( ) (1 ) ( ) ( ) u u u u u A A A r R R R R A r R R A      =  + = = − ＋ ∥ ＋ ∥ ∥    i 1 2 be1 R = R ∥R ∥r +  + = 1 3 5 be2 o 6 R R r R R ∥ ∥ 分析举例