Answer 4 y=f(u) ∑[o()x()+b 1+e % we=([0+b u1=1*0.1+3.1*0.35+0.5*04+0.5 NA1=1/1+eXp(-1*u1) %NA1=0.8682 Neurons are indexed byi weights are indexed byj b=bzas u2=1*0.27+3.1*0.73+0.5*0.15+0.31 0.35 0.7 NA2=1/(1+eXp(-1*u2) 0.35 %NA2=0.9482 Q.27 uY1=NA1*0.6+NA2*0.35+0.7 >NA2 0.1 Y1=1/(1+exp(-1*uY1) 1X=0.s/k Wi=3i=2) b=0.3 %Y1=0.8253 Hidden layer Neural Networks Ch9. ver. 9bAnswer 4 • % • u1=1*0.1+3.1*0.35+0.5*0.4+0.5 • NA1=1/(1+exp(-1*u1)) • %NA1=0.8682 • • u2=1*0.27+3.1*0.73+0.5*0.15+0.3 • NA2=1/(1+exp(-1*u2)) • %NA2=0.9482 • • u_Y1=NA1*0.6+NA2*0.35+0.7 • Y1=1/(1+exp(-1*u_Y1)) • %Y1= 0.8253 Neural Networks Ch9. , ver. 9b 29           =  + + = = = =       −  + = = i I i i x i u ω(i)x(i) b e y f u i I i 1 ( ) ( ) b where, 1 1 ( ) 1 