e)AVm=？dG=-SdT+VdP 4-(28=4g=n ap ap =-1.7x10-6C.V/Pa.mol=-1.7×106J/Pa.mol 1C.V=1J,1J=103dm3.Pa A,Vm=-1.7X10-3 dm3/mol f)△，Um°=△Hm°-P△，Vm=105KJ/mol 8 8 e）Δ rVm o =？ dG=-SdT+VdP T r m T r m r m P E S nF P G V ( ) ( ) 0 0 0 0   = − = −    = 1.7 10 C.V / Pa.mol 1.7 10 J / Pa.mol −6 −6 = −  = −  1C.V=1J，1J=103 dm3 .Pa Δ rVm o = - 1.7×10 -3 dm3 /mol f）ΔrUm o =Δ rHm o - PΔ rVm o =105KJ/mol