A force f is applied to the particle in a direction at an angle 0 with the rod(in x-y plane) Newton's Second law applied the tangential motion of the particle gives F=ma,=Fsin8 and a. =ar we obtain fsin 0=ma r rEsin e=rma.r F na s t=la I=mrA force is applied to the particle in a direction at an angle with the rod(in x-y plane). Newton’s Second law applied the tangential motion of the particle gives and , we obtain → F  Ft = mat = F sin  F m r  =  z sin a r t =  z Fsin m r  = z r r z mr  z  2 = → → F = m a 2  = I ,I = mr z z