(4)the work done in moving a test charge, from a point Pi to a DoIn P2, is independent of the path 0=∮Edl=E.dl+E aE.dl+ 1 p(bEdI (a)E.dl-/(bE·d W(a=-(aE·dl=-Q2(b)E·dl=W(b Integral form of the relation E=-Vv B E.d=-VV·dl=-dV, integrating over a path from pi to P2 yields P E. dl P /F1 Thus, from the integration of the electric field, only the difference btwn the potentials at two different points has been determined Setting the potential at infinity to be zero V1=V(oo)=0 E d