根据儡画凱对猕性可得 2sin t 2丌a<1 F[F()]=F[=]=2mf()= 0|o>1 上式西端同乘以1/2得( F(O)M sint. T ak <1 F[] 0(o>1 f(o) =m[(O+1)-(0-1)根据偶函数对称性可得 1 1 0 2 ] 2 ( ) 2sin [ ( )] [      = = =    f  t t F F t F 上式两端同乘以1/2得 [ ( 1) ( 1)] 1 1 0 ] sin [ = + − −      =       u u t t F f (t) −1 1  F() ( ) 2 1 F t f ()   1 t t  