Ⅷ An example,,cont. Slope (∑xy1)-n米41238-80.5)45125 38.7558 2)-nX2 968-810.5 °y- ntercept: y?b1x=45125?(38758)(10.5)=44.3140 So the best-fit linear model, rounding to the nearest tenth is j=44.3140+38.7558x≈44.3+38.8x o 2002 The Wadsworth GroupAn Example, cont. • Slope: • y-Intercept: So the “best-fit” linear model, rounding to the nearest tenth, is: b 1 = ( x i y i  ) – n×x ×y ( x i 2) – n×x 2  = 41238 – 8×(10.5)×(451.25) 968 - 8×(10.5) 2 = 38.7558 b 0 = y ? b 1 x = 451.25 ? (38.7558)(10.5) = 44.3140 y ˆ = 44.3140 + 38.7558x  44.3 + 38.8x © 2002 The Wadsworth Group