12 SOURCE WALL ABSORBER 马=Ih2 Iig-Ih +hale 2h2 I1(x)=h112 Gap 1 open Gap 2 open Gaps 1 and 2 open Gap 2 closed Gap 1 closed I2(x)h212 Wave intensity at each buoy 同时开放两个孔的效果： 112(x)=Ih1+h212=h12+lhz2+(hihz +hih)#I1(x)+12(x)同时开放两个孔的效果： 𝑰𝟏𝟐 𝒙 = 𝒉𝟏 + 𝒉𝟐 𝟐 = 𝒉𝟏 𝟐 + 𝒉𝟐 𝟐 + 𝒉𝟏 ∗𝒉𝟐 + 𝒉𝟐 ∗𝒉𝟏 ≠ 𝑰𝟏 𝒙 + 𝑰𝟐 (𝒙) 𝑰𝟏 𝒙 = 𝒉𝟏 𝟐 𝑰𝟐 𝒙 = 𝒉𝟐 𝟐