非均匀形核 rr(2-3cos 0+cos0) 液相L oLa 晶核a S1=2m(1-cos6) LB OaB oLB=OaB+OLa cos or so 基底B 2=/ur sin非均匀形核  L =   + L cos 2 (1 cos ) 2 S1 = r −    2 2 2 S = r sin (2 3cos cos ) 3 1 3 3 V = r −  + 