IV.Point Electric Dipole 1.Potential 「+ z=d/2 q r 0 (d/2)cose 2=-d/2 (d/2)cose o-品是- 2r- c-v9 Note:Φ(z=0)=0 6.641,Electromagnetic Fields,Forces,and Motion Lecture 5 Prof.Markus Zahn Page 8 of 116.641, Electromagnetic Fields, Forces, and Motion Lecture 5 Prof. Markus Zahn Page 8 of 11 IV. Point Electric Dipole 1. Potential 0 q 11 4 rr + − ⎡ ⎤ Φ= − ⎢ ⎥ π ⎣ ⎦ ε 2 2 2 d r xy z 2 + ⎛ ⎞ = + +− ⎜ ⎟ ⎝ ⎠ 2 2 2 d r xy z 2 − ⎛ ⎞ = + ++ ⎜ ⎟ ⎝ ⎠ Note: Φ= = ( ) z0 0