3)检验判断: 上临界值:a,下临界值:a (1)0<d<d1→ reject H (2)4-di <d<4= reject Ho B)du<d<4-du= not reject Ho (4)Otherwise, no conclusions3) 检验判断： U L 上临界值: , d d 下临界值: 0 0 0 (1) reject (2) 4 - 4 reject (3) 4 not reject (4) Otherwise, no conclusions L L U U o d d H d d H d d d H         − 