(6)(arcsin x) d(arcsin x) dx 1-x (arccos x) d (arccos x)=-dx (arctan x) 1+x 2 d(arctan x) 1+x (arc cot x) d (arc cot x) dx 1+x 1+x2 1 1 (6)(arcsin ) x x −  = 2 1 (arcsin ) x dx d x − = 2 1 1 (arccos ) x x −  = − 2 1 (arccos ) x dx d x − = − 2 1 1 (arctan ) x x +  = 2 1 (arctan ) x dx d x + = 2 1 1 (arc cot ) x x +  = − 2 1 (arc cot ) x dx d x + = −