对输入(x12…,xk)得输出: ∑(4(x)入“A4(x)(1+p1x+…+p ∑(4(x)入…4(x) i=1 B A1(x1)A。八Ak(xk ∑(4(x1)入A4(x) y=∑B(P+n1x1+·+pxk) ∑(p月+p1x1B1+··+Dkxk月B)( ) ( )  = = • • • • • • • + + • • • + = n i k i k i n i k i i k i i k i k i A x A x A x A x p p x p x y 1 1 1 1 1 1 0 1 ( ) ( ) ( ) ( ) ( ) 对输入(x1 ,..., xk )，得输出： ( ) ( ) = • • • • • • = n i k i k i k i k i i A x A x A x A x 1 1 1 1 1 ( ) ( ) ( ) ( ) 令  ( ) ( ) 0 1 1 0 1 1 k i i i k i i i n i k i k i i n i i p p x p x y p p x p x     = + + • • • + = + + • • • +  则 