Acceleration Vector graphical analysis method Knowns:and direction of ae ag=aA+a"Ba+a'BA Mag:?√o2laB? A Dire:√√B-→A⊥BA a Select a scale ua m/s2/mm, 0 Draw p'a'from p',let a=uap'a then:ae=μapb' b aBA=μab"b' direction:b”+b' b a aBA=μab'a' Dire: a'→b For ac:ac=a+a"ca+a'cA unsolvable! Mag:?√o2ca-7 Dire:？√C→A⊥CA and:ac=as+a"ce+a'cB unsolvable! Mag:？√o2lcB Dire:？√C→B⊥CB Combine the two eqs: ac=aA+ancA+acA=ae+ance+acB ?√√？ We can find: ac=μap'c'dire:p'→c3 aca=μac"c'dire:c+c acs=μac'c”dire:c→c3 1010 Vector graphical analysis method b’ B A C then：aB＝μap’ b’ Select a scaleμa m/s2/mm， Draw p’a’ from p’ , let aA＝μap’ a’ b” Knowns： ωand direction of aB aB＝aA + an BA+ at BA at BA＝μab”b’ direction: b” → b’ aBA＝μab’ a’ Dire: a’ →b’ Mag： Dire： ? ⊥BA ? √ √ √ B→A ω2lAB aA aB a’ p’ Acceleration aC＝aA + an CA+ at CA ＝ aB + an CB+ at CB and： aC＝ aB + an CB+ at CB unsolvable！ Combine the two eqs： For ac： aC＝aA + an CA+ at CA unsolvable！ We can find: at CA＝μac”’c’ at CB＝μac’c” dire：c”’ → c’ dire：c” → c’ dire：p’ → c’ ? ? √ √ ? √ √ ? √ √ √ √ √ √ B A C Mag： ? Dire： ? √ √ ω2lCA C→A ? ⊥CA Mag： ? Dire： ? √ √ ω2lCB C→B ? ⊥CB b’ b” a’ p’ c”’ c” c’ aC＝μap’ c’