(1) aoy2(0), y2(2)=-aoy2()=(-a0)y2(0 y2(k)=(-a0)y2(0),k≥0 比较y+ao0y=0,y(0)已知, D(p)=p+ao=0→=-a0 y2()=Aee()=y(0)e8(1) 东南大学移动通信国家重点实验室∴ (2) (1) ( ) (0) (1) (0), 2 0 0 0 zi zi zi zi zi y a y a y y a y = − = − = − y (k) = (−a0 ) yzi(0) , k ≥ 0 k zi "" 比较 0, (0 ) 0 − y′ + a y = y 已知， 0 0 0 D( p) = p + a = ⇒ λ = −a ∴ ( ) ( ) (0 ) ( ) 0 y t Ae t y e t t a t zi = ε = ε λ − − 东南大学移动通信国家重点实验室