c=0.14mA B ≈7.14kQ 电压放大倍数求解过程如下 26mV The=rb+(1+B ≈10.7kQ 26mv red=rb+(1+B) 2.74k9 PR2∥+(+)Al2165 2 be2 BRa +(1+B)R24 A1=An1·A 97  + = = − = − 7.14k 0.14mA C 2 c1 E4 E4 BEQ4 c2 CQ4 C2 B4 C2 R R I I R U R I I I I I ＝  电压放大倍数求解过程如下： = + +   = + +   2.74k 26mV (1 ) 10.7k 26mV (1 ) EQ4 be4 bb' EQ2 be2 bb' I r r I r r     297 18 (1 ) 16.5 2 [ (1 ) ] 1 2 be4 e4 c4 2 be2 c2 be4 e4 1 － ∥ =    − + + = −  + + = u u u u u A A A r R R A r R r R A         