Stresses in Springs Removed portion exerts force F and torsion T on remaining part Maximum stress in wire is: Tr F t 十 max A ·T=F*D/2=torque ·r=wire radius ·J=πd4/32=polar moment of inertia A=wire cross-sectional areaStresses in Springs • Removed portion exerts force F and torsion T on remaining part • Maximum stress in wire is: max Tr F J A t = ± + • T = F*D/2 = torque • r = wire radius • J = pd 4 /32 = polar moment of inertia • A = wire cross-sectional area