10.1.2函数的嵌套调用顺序调用mainint main(void)y = fact(3);factmypowz = mypow(3.5, 2);maindouble fact(int n)factAmypowdouble mypow(double x, in n)t110.1.2 函数的嵌套调用 ◼ 顺序调用 int main(void) { . y = fact(3); . z = mypow(3.5, 2); . } double fact(int n) { . } double mypow(double x, in n) { . } main fact mypow main fact mypow