The value of the even part (and the odd part for that matter at t=0 is ambiguous as it depends on how the plot for r (t) is defined at t =0. The plots in this solution assume that the value of a(t)at t=0 is halfway between 0 and 2, i.e. 1. Using a different definition you may get an even part that is discontinuous at t=0. This is also correct provided it is consistent with your assumption of what the value of a(t) is at the discontinuity. For instance, if you assume that a(0)=2, then the plot of the even part will have a"spike"at t=0 of height 2xo(t) −4 −2 2 4 t 1 -1 The value of the even part (and the odd part for that matter) at t = 0 is ambiguous as it depends on how the plot for x(t) is defined at t = 0. The plots in this solution assume that the value of x(t) at t = 0 is halfway between 0 and 2, i.e. 1. Using a different definition you may get an even part that is discontinuous at t = 0. This is also correct provided it is consistent with your assumption of what the value of x(t) is at the discontinuity. For instance, if you assume that x(0) = 2, then the plot of the even part will have a “spike” at t = 0 of height 2. 9